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2x^2+1.8x-0.4=0
a = 2; b = 1.8; c = -0.4;
Δ = b2-4ac
Δ = 1.82-4·2·(-0.4)
Δ = 6.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.8)-\sqrt{6.44}}{2*2}=\frac{-1.8-\sqrt{6.44}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.8)+\sqrt{6.44}}{2*2}=\frac{-1.8+\sqrt{6.44}}{4} $
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